More Probability

Here are a few questions that will involve all of the material that we’ve covered so far. Complete these before our next lesson on Thursday.

Page 548–552 questions 6, 12, 13, 14, 16, 18, 20, 25

Calculus + Induction

Here’s the question we considered on Thursday. Now that you’ve got a solution for parts 1 and 2, complete part 3 as a homework assignment due on Tuesday, the 25th of October.

The function \(f\)is defined by \(f(x) = e^x \sin x\).

  1. Show that \(f”(x) = 2e^x \sin \left(x+\frac{\pi}{2}\right)\).
  2. Obtain a similar expression for \(f^{(4)}(x)\).
  3. Suggest an expression for \(f^{(2n)}(x), n \in \mathbb{Z}^+\), and prove your conjecture using mathematical induction.

Solids of Revolution

Today we saw how to use a definite integral to calculate the volume of a solid of revolution. (Some textbooks will refer to this as finding a “volume of revolution.”)

The solid we studied today is shown below, and the equation used to generate this solid was \(y=\cos x +2\), with \(x\) running from 0 to 5. Can you use your knowledge of solids of revolution to derive the formulas for

  • the volume of a cone with height \(h\) and a base of radius \(r\), \(V=\frac{1}{3}\pi r^2h\)
  • the volume of a sphere of radius \(r\), \(V=\frac{4}{3}\pi r^3\)

Integration by Substitution

As discussed on Thursday, try the following questions this weekend. Some may not be as difficult as they first appear, and others…

Complete pages 780–781 questions 26, 28, 33, 45, and 49.
If you’re interested in (what may be) a challenge, also try questions 43, 48, and 50.

Operations with Taylor Series

From Chapter 30 of the Cambridge book, complete the following questions for Wednesday this week.

page 5 question 5,
page 11 questions 4 and 5,
page 14 question 2 a),
page 15 question 9,
page 19 question 8.

Fun with Comparison Tests

Your challenge tonight is to come up with a series that can be shown to converge using (either version of) the comparison test. We’ll vote on the best example tomorrow. Here’s my entry.

\[\sum_{n=1}^\infty \frac{1}{2^n-n^2}\]