Lines in 3D

Try to complete the following questions for Monday’s lesson.

  1. Find the distance of the point  \(A(-1,1,2)\) to the line \[\displaystyle{\vec{r}=\begin{bmatrix}1\\-2\\3\end{bmatrix}+\lambda \begin{bmatrix}-2\\1\\1\end{bmatrix}}\]
  2. The lines below intersect at a point \(A\). Use an algebraic method to find the coordinates of  \(A\), then verify your answer using GeoGebra.
    \[L_1: \vec{r}=\begin{bmatrix}-1\\-1\\4\end{bmatrix}+\lambda \begin{bmatrix}-2\\1\\1\end{bmatrix}\] \[L_2: \vec{r}=\begin{bmatrix}-2\\0\\7\end{bmatrix}+\lambda \begin{bmatrix}-6\\4\\8\end{bmatrix}\]
  3. In 2D, any two non-parallel lines will have a point of intersection. In 3D, two lines can be non-parallel and have no point of intersection; such lines are called skew lines.
    Show that \(L_1\) from question 2 and \(L_3\) below are skew lines.
    \[L_3: \vec{r}=\begin{bmatrix}-2\\5\\12\end{bmatrix}+\lambda \begin{bmatrix}-6\\4\\8\end{bmatrix}\]

Vector Equations of Lines 3

Find the distance of the point \(A(-3,1)\) to the line
\[\displaystyle{\vec{r}=\begin{bmatrix}1\\2\end{bmatrix}+\lambda \begin{bmatrix}-2\\3\end{bmatrix}}\]

using the method outlined below.

  1. Find an expression for an arbitrary point \(D\) on the given line.
  2. Using the expression you’ve produced, find a general expression for the vector \(\overrightarrow{AD}\).
  3. Where \(\vec{b}\) is the direction vector of the given line, use the dot product \(\overrightarrow{AD}\cdot\vec{b}\) to find the coordinates of the point on the line closest to \(A\). Hence, find the distance from \(A\) to the line.

Vector Equations of Lines 2

Complete the following question for our lesson tomorrow. In the first instance, use the Cartesian equation to find your solution, then see of you can find a vector-based solution to the same problem.

Find the distance of the point \(A(1,3)\) to the line
\[\displaystyle{\vec{r}=\begin{bmatrix}4\\2\end{bmatrix}+\lambda \begin{bmatrix}4\\1\end{bmatrix}}\]

Vector Equations of Lines

Complete the following questions for tomorrow’s lesson.

  1. Find a vector equation of the line passing through \(A(2,5)\) and \(B(6,-1)\).
  2. Find a different vector equation for the same line.

Applications of Vectors

As discussed in class last week, complete page 418 question 18 for tomorrow’s lesson.

For other examples of applications in physics, I suggest you also look at questions 28 and 29 on page 419.

Working with Vectors

Here’s a short question to consider tonight.

Given points A and B, let C be the midpoint of the line segment from A to B. Find an expression for \(\vec{c}\) in terms of  \(\vec{a}\) and  \(\vec{b}\) .

Vectors

The vectors questions for tomorrow’s lesson are included below. (Thanks to Damin for reminding me to post these!)

Get as far as you can with these; you’ll also have the first 10 or 15 minutes of tomorrow’s lesson to work on these before we discuss the solutions.

Complete pages 407–409 questions 1, 3, 6, 10, 12, 19, 20, 22

Trigonometry Test

We’ll have a test on trigonometry (the material covered in Chapters 7 and 8 in the textbook) on Monday, 18 April.

The following questions will be help you prepare.

Pages 346–349 questions 1, 4, 5, 6, 8, 9, 10, 13, 17–23

Pages 394–397 questions 1, 5–9, 11, 13, 14, 17