11 HL: Vector and Cartesian Equations of Planes

Try the (challenge) question below before our next class. For an extra challenge, can you post your solution below using \(\LaTeX\)? (See here for a quick tutorial.)

Find a vector equation of the plane whose Cartesian equation is \(2x+y-z=4\).

Hint 1
Can you find three points that lie on the plane? Those three points might be useful…
Hint 2
Those three points can be used to find two useful vectors…

11 HL: Planes and Normals

Complete the questions in the PDF file attached before next class. (Questions 1 b) and 3 a) are challenge questions, but you might be able to figure these out using the material we’ve covered in the past few lessons… see the hint below.)

Hints
A line with just the right direction, in just the right location, might intersect the plane in just the right point…

11 HL: Lines & Planes

Complete the following question before our next class.

Find the point of intersection of the line \( \frac{x-2}{5}=\frac{y+2}{2}=\frac{z-1}{3}\) and the plane \(2x-3y+z=0\).

11 HL: The Cross Product

Complete the following questions before our next class.

Exercise 12N.1 questions 1, 4, 8, 10
Exercise 12N.2 questions 3, 4, 5
Exercise 12N.3 questions 2, 5

11 HL: Vector Equations of Lines in 3D

Complete the following questions before our next class.

Exercise 13A questions 4, 5ac, 6ab

Also, (as a challenge question) can you answer question 2 from class? Both questions are shown below.

  1. Find the vector equation of the line passing through \(A(1,-1,4)\) and \(B(3,3,-1)\).
  2. Find the distance of the point \(A(1,2,3)\) to the line given by
    \[\vec{r}=\begin{bmatrix}4\\2\\1\end{bmatrix}+\lambda \begin{bmatrix}4\\1\\-1\end{bmatrix}\]

11 HL: Finding Vector Equations of Lines

Complete the following questions before our next class.

Exercise 13A questions 1–3

Also, see if you can finish the question below. (Vector methods not required!) We’ll discuss a vector approach to this sort of question in the lessons to come.

Find the distance of the point \(A(1,3)\) to the line \(y=2x-2\).